(Q6) From the top of a building, the angle of elevation of the top of a cell tower is 60^o and the angle of depression to its foot is 45^o. If distance of the building from the tower is 7 m, then find the height of the tower.

Solution :

Angle of elevation of the top of the tower = 60°.

Angle of depression to the foot of the tower = 45°.

Distance between tower and building = 7 m.

Let the height of the building = x m and tower = y m.

From the figure

∴ x = m.

Put x value

√ = y -

∴ y = + √

y = (√ + ) = ×2.732 = .124m